Slope = change in y/ change inx Slope is denoted as m in the following equation
y=mx+b (called the y-intersept form)
Where b is the y intercept, and x and y are the coordinates
To solve for b, plug in the values for m, x, and y, and solve for b in the way you normally solve an algebraic equation
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
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The equation of a line can be written in a format called "point slope form". Equations in this form look like y - y1= m(x - x1). In this formula (x1,y1) is any point on the line, m is the slope, x is the input (or dependent variable) and y is the output or dependent variable. Using this, and a given slope and point, you can construct the equation for a line. The y-intercept is the point where a line crosses the y-axis. You don't know where on the y-axis, but you know that the x-value of any point of the y-axis is 0. Therefore, you can solve for the y-intercept bus substituting 0 for x and solving for y.
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
Assuming that the point is located at (1,1) then the equation is: y = -3x + 4 We know this by multiplying the slope by the x of the point given, and finding the difference between this value, and the y value of the point. 1 - (-3) is 4, hence the +4 in our equation.
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If the algebraic equation is linear, in the form y = mx + b, the slope is simply m; the difference in y of any 2 points divided by the difference in x of those points (rise over run). If the equation is non-linear, the slope is the first derivative of that equation, from calculus. You woul need to know calculus to solve in this case. The slope will vary from point to point, unlike the linear case, where slope is constant.
The slope of a curved line changes as you go along the curve and so you may have a different slope at each point. Any any particular point, the slope of the curve is the slope of the straight line which is tangent to the curve at that point. If you know differential calculus, the slope of a curved line at a point is the value of the first derivative of the equation of the curve at that point. (Actually, even if you don't know differential calculus, the slope is still the value of the function's first derivative at that point.)
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,
This is simple algebra. You should know that parallel lines have the same slope. So you would take the slope of the line that is given to you and set it up in the equation y= mx + b. m stand for your slope and you would take the point that it gives you (3, -1) and plug it into y = mx + b (along with your slope) and solve for b..once you've solved for b, you can set up your equation because you know your slope (m) and y-intercept (b). If you are having trouble finding the slope, just solve the equation for y. Get y on one side of the equation. The number that is with x will be your slope. Good luck!
We usually denote the slope of a line as M. Horizontal lines have a slope of zero. Mhorizontal line = 0 Verticle lines have a slope that is undefined. Note that the slope is not infinite, but is undefined. Mvertical line = undefined To write the equation of a horizontal or vertical line, we need to know if it's going to be a slope-intercept form or a point-slope form.
i dont know 8x+5y=89