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In how many ways can 7 students line up a a ticket booth?
There are 5040 ways.
How many ways can a group of 3 students be chosen from a class of 30 students?
Well, honey, there are 30 students in the class, and you want to choose a group of 3. So, you're looking at a classic combination situation. The formula for combinations is nCr = n! / r!(n-r)!, so in this case, it's 30C3 = 30! / 3!(30-3)! = 4060 ways to choose those 3 lucky students. It's like picking the winning lottery numbers, but with fewer tears and more math.
How many ways can seven students line up to buy concert tickets?
7
How many ways to line 5 students up in a class of 20?
20*19*18*17*16 = 1860480 ways.
A committee of 8 students is to be selected from a class consisting of 19 freshmen and 34 sophomores in how many ways can a committeee with at least 1 freshman be selected?
This number is 19(52)(52-1)(52-2)(52-3)(52-4)(52-5)(52-6)(52-7), or approximately 5.89 X 1014. The reasoning is as follows: Any one of the 19 freshman can be selected first. After this choice is made, there are 52 remaining persons (34 + 19 -1) from among whom the second position on the committee can be chosen, 52 -2 remaining persons for the third position, etc.)
Is this a permutation In how many different ways could a committee of 5 students be chosen from a class of 25 students?
6,375,600
How many ways can an EMT union committee of 5 be chosen from 25 EMTs?
125
How many different ways can 1 committee of 5 students be selected from a class of 25?
53,130 ways.
How many ways can a committeee of 6 be chosen from 5 teachers and 4 students if the committee must includes three teachers and three students?
There are 10 different sets of teachers which can be combined with 4 different sets of students, so 40 possible committees.
How many ways can a president vice president and secretary be chosen for a committee of 9 people?
There are 9*8*7 = 504 ways.
How many ways can an adviser chosen 4 students from a class of 12 if they are given a different task?
There are 11880 ways.
How many ways can a committee consisting of a lead second and alternate be chosen out of 309?
309*308/2 = 47586
How many ways can a committee of 3 students be chosen from a total count of 1514 students?
The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864
2 students have to be chosen as monitor in a class of 36 how many ways to done this?
36 x 35/2 ie 630
There are 20 students participating in a math bee How many ways can the students be chosen to go first second third and fourth?
20 * 19 * 18 * 17 = 116,280 ways This is Permutation: nPr = n! / (n-r)!
In how many ways can a committee of three men and four women be formed from a group of 10 men and 10 women?
I'm going with 25,200 3 men out of 10 may be chosen in 10C3 ways = 10 ! / 3! 7 ! = 120 ways. 4 women may be chosen out of 10 in 10C4 = 10 ! / 4! 6! ways = 210 ways. Therefore, a committee with 3 men and 4 women can be formed in 120 x 210 = 25,200 ways.
How many different ways can 4 kids be chosen to serve on a committee from a group of 30 kids?
40 x 39 x 38 x 37 = 2193360
