Whatever you choose. The function, itself, imposes no restrictions on the domain and therefore it is up to the person using it to define the domain. Having defined the domain, the codomain, or range, is determined for you.
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x-intercept happens when y=0 0=x2+6x-7 0=(x - 1)(x + 7) x-intercepts are x=1 and -7
If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
x2-6x-27 = (x+3)(x-9) when factored
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
In the equation x2 = 6x - 9, all terms must be moved to one side of the equals sign, giving x2 - 6x + 9 = 0. This becomes factorable to (x -3)(x-3).