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What are the X-intercept of the graph of the following Equation y equals x2 plus 6x-7?
x-intercept happens when y=0 0=x2+6x-7 0=(x - 1)(x + 7) x-intercepts are x=1 and -7
What is the factored form of x2 6x 8?
If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
What is the factor of this trinomial x2-6x-27?
x2-6x-27 = (x+3)(x-9) when factored
X2 - 6x equals -8?
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
Find the value or values of x in the quadratic equation x2 equals 6x-9?
In the equation x2 = 6x - 9, all terms must be moved to one side of the equals sign, giving x2 - 6x + 9 = 0. This becomes factorable to (x -3)(x-3).
How do you find the vertex and graph?
y = - x2 +6x - 5.5
Factor 6 x2 - 11x?
x(6x - 11)
How do you graph y equals x2 plus 6x plus 7?
y = x2 + 6x + 7a = 1, b = 6, c = 7Since a is positive, the graph opens upward. You can find the vertex coordinates (-b/2a, f(-b/2a)) = (-3, f(-3)) = (-3, -2), so the equation of the axis of symmetry is x = -b/2a = -3, plot the y-intercept point (0, 7), plot the point (-b/a, 7) = (-6, 7), and draw the graph that passes through these points.Or complete the square.y = x2 + 6x + 7y = x2 + 6x + 9 - 9 + 7y = (x2 + 6x + 9) - 2y = (x + 3)2 - 2So start with the graph of y = x2 whose vertex is at the origin. Move it 3 units to the left, and 2 units do
What is the factor of x2-5x-66?
x2-5x-66 x2-11x+6x-66 x(x-11)+6(x-11) (x+6)(x-11)
What is the range of y equals x2 plus 6x plus 11?
y ≥ 11
How do you factor x2 6x-2?
x2 + 6x - 2 can not be factored
How to Graphs Y equals x2 plus 6x plus 7?
y = x2 + 6x + 7a = 1, b = 6, c = 7Since a is positive, the graph opens upward. You can find the vertex coordinates (-b/2a, f(-b/2a)) = (-3, f(-3)) = (-3, -2), draw the axis of symmetry, x = -b/2a = -3, plot the y-intercept point (0, 7), plot the point (-b/a, 7) = (-6, 7), and draw the graph that passes through these points.Or complete the square.y = x2 + 6x + 7y = x2 + 6x + 9 - 9 + 7y = (x2 + 6x + 9) - 2y = (x + 3)2 - 2So start with the graph of y = x2 whose vertex is at the origin. Move it 3 units to the left, and 2 units down.
How do you solve x2 6x 27?
please help on this x2+6x+27=
How do you Factorise this x2 plus 6x?
x2 + 6x = x*(x + 6)
If x is a positive integer solve x2 6x 16?
Um.......is it x2+6x or x2-6x. I think your missing some things here champ
Factorise x2 plus 6x-55 equals?
(x-5)(x+11)
X2 - 6x - 16?
x2 - 6x - 16 = (x - 8)(x + 2)
