i am not sure about how to solve the values for a theta graph but i know it looks like a spiral and you can plot these points if you draw a square and halve it and in each of the centres of the square is another point of theta.
then you need the gradient of the line so if you have f(x)=θ
then what is f(x)' which would be the gradient by the way f(x)' is another way of saying differentiated or dy/dθ
If r-squared = theta then r = ±sqrt(theta)
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
If sin2(theta) = 0, then theta is N pi, N being any integer
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
The question contains an expression but not an equation. An expression cannot be solved.
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
-1
4*cos2(theta) = 1 cos2(theta) = 1/4 cos(theta) = sqrt(1/4) = ±1/2 Now cos(theta) = 1/2 => theta = 60 + 360k or theta = 300 + 360k while Now cos(theta) = -1/2 => theta = 120 + 360k or theta = 240 + 360k where k is an integer.
d theta divided by 4.28 is not an equation or inequality: it is an expression. An expression cannot be solved.
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)