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i am not sure about how to solve the values for a theta graph but i know it looks like a spiral and you can plot these points if you draw a square and halve it and in each of the centres of the square is another point of theta.

then you need the gradient of the line so if you have f(x)=θ

then what is f(x)' which would be the gradient by the way f(x)' is another way of saying differentiated or dy/dθ

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Q: How do you solve for theta?
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If r-squared = theta then r = ±sqrt(theta)


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You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.


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