cos2(theta) = 1
cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0
cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
If r-squared = theta then r = ±sqrt(theta)
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
If r-squared = theta then r = ±sqrt(theta)
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
The answer depends on what theta is and the units of its measurement.
0.75
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
It also equals 13 12.
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
If tan theta equals 2, then the sides of the triangle could be -2, -1, and square root of 5 (I used the Pythagorean Theorem to get this). From this, sec theta is negative square root of 5. It is negative because theta is in the third quadrant, where cosine, secant, sine, and cosecant are all negative.