(x - 8)(3x + 4)
3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
3(x + 4)(x + 1)
It is: 3x*(x+7)
x(3x - 2)
3x2 + x = x*(3x + 1)
If that's -18y2, the answer is (3x - 2y)(x + 9y)
(3x + 3y)(x + y) = 3(x + y)2
The sum of the coefficients is 3 - 7 + 4 = 0 so (x - 1) is a factor. Thus, 3x2 - 7x + 4 = 3x2 - 3x - 4x + 4 = 3x(x - 1) - 4(x - 1) = (3x - 4)(x - 1)
(3x - 2)(x + 8)
13
-1