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How do you find the vertical asymptote for the logarithmic function f of x equals log x?
Wiki User
∙ 10y ago
The only way I ever learned to find it was to think about it.
The function f(x) = log(x) only exists of 'x' is positive. As 'x' gets smaller
and smaller, the function asymptotically approaches the y-axis.
Wiki User
∙ 10y ago
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What is the domain range asymptote and intercept of the equation y equals 4 times 2 exponent x?
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
What is the formula for a rational function with x intercepts at x equals 3 and x equals negative 2. y intercept at y equals 12. a hole at x equals 1 and no horizontal asymptote?
f(x) = 2*(x-3)*(x+2)/(x-1) for x ≠1
Is 2y equals 8 a linear function?
Yes, 2y = 8 is a linear function. 2y = 8 is the same as y=8/2, or y=4, which is a vertical line.
Is y equals 6x plus 9 a function?
Well, f(x) = 6x + 9 is a function of x {it passes the vertical line test}. but y = 6x + 9 is an equation {linear equation of two variables}
A feature that is common to all exponential functions of the form F of x equals bx is that they have a common horizontal asymptote at the negative axis?
x axis
True or False if a rational function Rx has exactly one vertical asymptote then the function 3Rx should have the exact same asymptote?
It will have the same asymptote. One can derive a vertical asymptote from the denominator of a function. There is an asymptote at a value of x where the denominator equals 0. Therefore the 3 would go in the numerator when distributed and would have no effect as to where the vertical asymptote lies. So that would be true.
How do you find the horizontal asymptote of a logarithmic function where x equals 7.5 and y equals 50?
One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.
Which function has the following a vertical asymptote at x equals -4 horizontal asymptote at y equals 0 and a removable discontinuity at x equals 1?
2x-2/x^2+3x-4
The graph of a logarithmic function in the form of F x equals logb x will always have a vertical asymptote at the y-axis and an x-intercept at the point?
The point you desire, is (1, 0).The explanation follows:b0 = 1, for all b; thus,logb(1) = 0, for all b.On the other hand, logb(0) = -∞,which explains the vertical asymptote at the y-axis.
Does y equals log5x have an asymptote?
Yes, the asymptote is x = 0. In order for logarithmic equation to have an asymptote, the value inside log must be 0. Then, 5x = 0 → x = 0.
Do logarithmic functions have vertical asymptotes?
Yes. Take the functions f(x) = log(x) or g(x) = ln(x) In both cases, there is a vertical asymptote where x = 0. Because a number cannot be taken to any power so that it equals zero, and can only come closer and closer to zero without actually reaching it, there is an asymptote where it would equal zero. Note that transformations (especially shifting the function left and right) can change the properties of this asymptote.
What is the domain of the function fx equals 3 over x plus 2?
- 2 makes this zero and provides the vertical asymptote. So, from - infinity to - 2 and from - 2 to positive infinity
How do I determine the domain and the equation of the vertical asymptote with the equation f of x equals In parentheses x plus 2 end of parentheses minus 1?
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded. If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
For all values of a and b that make Fx equals a bx a valid exponential function the graph always has a horizontal asymptote at y equals 0?
True
Which best describes the asymptote of an exponential function of the form Fx equals bX?
f(x) = bX is not an exponential function so the question makes no sense.
Does 5 equals log 5 to the x have an asymptote?
no
Determine the equation of any vertical asymptote and the value of x for any hole in the graph of the rational function fx x-2 over xsquared-x-2?
Asymptote's occur when your equation has a denominator of zero Holes may occur when your equation has both a numerator and denominator of zero So... The equation for the denominator equals zero is: x2-x-2 = 0 The equation for both the numerator and denominator equals zero is x - 2 = x2-x-2 = 0 For interests sake... lets solve it. ---- x2-x-2 = 0 (x+1)(x-2) = 0 x = -1, 2 x - 2 = x2-x-2 = 0 x - 2 = 0 x = 2 A vertical asymptote occurs at x = -1 A vertical asymptote or hole may appear at x = 2
