64x^(2) - 5 = 11
Equate to zero , by subtracting '11' from both sides.
Hence
64x^(2) - 16 = 0
Algebraically rearrange
(8x)^(2) - 4^(2) = 0
We now have two squared terms with a negative between them. This factors to :-
(8x - 4)(8x + 4) = 0 Note the different signs in each brackets.
Hence
8x - 4 = 0
8x = 4
x - 4/8
x = 1/2
&
8x + 4 = 0
8x = -4
x = -4/8
x = -1/2
So the two solutions are x = 1/2 & x = -1/2
NB Twosquared terms with a POSITIVE(+) between them , does NOT factor.
X + 11 = 37. subtract 11 from both sides; X = 37 - 11 = 26.
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
This question has already been answered in detail and the value of x is 11/15 which when substituted into the equation results in: 12/11 = 12/11
x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
2x/7 = 11 Multiply both sides by 7: 2x = 77 Divide both sides by 2: x = 77/2 = 38.5
h = +11 and/or -11
its 10
a = 4
a=11
It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
3x-11 for x=9
9y subtract 11 equals 7
11×11×11=1331 You would solve this by showing 11, 11 times.
You subtract 11 from both sides and r equals negative 7. See... r+11=3 -11 -11 r=7
32
Answer:12y=132y=132/12=11
r + 11 + 8r = 29