x0 and y0 usually denote the original condition or value for the variables x and y or may represent the first values in an array of values. Some final condition my be represented by x1 or y1 or x12 or y12 depending on how many conditions you want the values of x and y for.
If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
y=x+7 x - intercept set y to 0 0=x+7 -7 -7 -7=x (-7,0) y - intercept set x to 0 y=0+7 y=7 (0,7) (-7,0) , (0,7)
3x + 2y = x + y y = -2x to find y-int set x equal to zero y = -2(0) = 0 or... 3(0) + 2y = (0) + y 2y - y = 0 y = 0 y-intercept is zero
at y=6.Make x==0 // then you get the y interceptthen y=0+6solve for y, y=6
x + 3y = 4 -x + 2y = -4 Simultan eous eq'ns. Eliminate 'x' by adding. 4 Hence 5y = 0 y = 0 When y = 0 Substitute x + 3(0) = 4 x + 0 = 4 x = 4 So the answer as a coordinate pairs is ( x,y) = ( 4,0)
When x = 0, the point that has (0, y) coordinates will be on the y-axis for any y.
If you mean x/2 + y/3 = 0 (ZERO, not the letter O) then yes. The equation can be rewritten as x/2 = - y/3 or x = (-2/3)y
x+0=y x means any number plus 0 equals y which is the answer
If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
If a set, S, has an additive identity, O, then for every element x, of S, here exists an element y (also in S) such that x + y = O = y + x. O is denoted by 0, and y by -x.
x-y=0 x=y so you will use that in the other equation by substituting every y with x 2x+y=0 2x+x=0 3x=0 x=0/3 x=0 then use that in the previous equation by substituting every x with 0 x=y 0=y; y=0 finally x=0 and y=0
if x:=x(y) then y=0 => x=x(0)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: y = -15x+60 then 15x+y = 60 When y = 0 then x = 4 When x = 0 then y = 60 Coordinates of the line are: (4, 0) and (0, 60)
take take you out hugs kisses hugs
If by area you mean X*Y it would be -49 (or 49, if you assume area to be positive). (X=7, Y=-7) when X+Y^2=56 and X+Y=0.