If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
y=x+7 x - intercept set y to 0 0=x+7 -7 -7 -7=x (-7,0) y - intercept set x to 0 y=0+7 y=7 (0,7) (-7,0) , (0,7)
3x + 2y = x + y y = -2x to find y-int set x equal to zero y = -2(0) = 0 or... 3(0) + 2y = (0) + y 2y - y = 0 y = 0 y-intercept is zero
at y=6.Make x==0 // then you get the y interceptthen y=0+6solve for y, y=6
To find the Y-intercept, plug 0 in for X, so you have 0+Y=-3, or Y=-3. Therefore, your Y-intercept is at the point (0,-3). You do the same thing to find the X-intercept, only reversed. X+0=-3, so X=-3. This intercept is at (-3,0).
If you mean x/2 + y/3 = 0 (ZERO, not the letter O) then yes. The equation can be rewritten as x/2 = - y/3 or x = (-2/3)y
When x = 0, the point that has (0, y) coordinates will be on the y-axis for any y.
If a set, S, has an additive identity, O, then for every element x, of S, here exists an element y (also in S) such that x + y = O = y + x. O is denoted by 0, and y by -x.
If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
x+0=y x means any number plus 0 equals y which is the answer
x-y=0 x=y so you will use that in the other equation by substituting every y with x 2x+y=0 2x+x=0 3x=0 x=0/3 x=0 then use that in the previous equation by substituting every x with 0 x=y 0=y; y=0 finally x=0 and y=0
if x:=x(y) then y=0 => x=x(0)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: y = -15x+60 then 15x+y = 60 When y = 0 then x = 4 When x = 0 then y = 60 Coordinates of the line are: (4, 0) and (0, 60)
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There are two simple strategies to compare two numbers, X and Y: you can calculate X - Y. If X - Y > 0 then X > Y, if X - Y = 0 then X = Y and if X - Y <0 then X < Y. Or you can calculate X/Y. Provided both are greater than 0, if X/Y > 0 then X > Y if X/Y = 1 then X = Y if X/Y <1 then X < Y