x0 and y0 usually denote the original condition or value for the variables x and y or may represent the first values in an array of values. Some final condition my be represented by x1 or y1 or x12 or y12 depending on how many conditions you want the values of x and y for.
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If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
y=x+7 x - intercept set y to 0 0=x+7 -7 -7 -7=x (-7,0) y - intercept set x to 0 y=0+7 y=7 (0,7) (-7,0) , (0,7)
3x + 2y = x + y y = -2x to find y-int set x equal to zero y = -2(0) = 0 or... 3(0) + 2y = (0) + y 2y - y = 0 y = 0 y-intercept is zero
at y=6.Make x==0 // then you get the y interceptthen y=0+6solve for y, y=6
By Simultaneous Equations. Assuming you mean 5x + 3y + 20 = 0 2x - y - 14 = 0. We will eliminate 'y' by multiplying the bottom eq'n by '3' and then adding. Hence 5x + 3y + 20 = 0 6x - 3y -42 = 0 Add 11x -22 = 0 11x = 22 x = 22/11 x = 2 when x= 2 2(2) - y - 14 =0 4 - y - 14 = 0 -y - 10 = 0 y = -10 So the point of intersection in ( x.y.) form is ( 2, -10).