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If f(x) 3x2 - x find f(-2).?
Wherever there is an x substitute -2 and calculate the resulting sum: f(x) = 3x² - x → f(-2) = 3 × (-2)² - (-2) = 3 × 4 + 2 = 12 + 2 = 14
What is the derivative of fx where fx equals 2x-3 all under square root?
f(x) = √(2x -3) f(x) = (2x - 3)^(1/2) f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2) f'(x) = (2x - 3)^(-1/2) f'(x) = 1/[(2x - 3)^(1/2)] f'(x) = 1/√(2x -3)
What is the range of a a function f when it is defined by f x 2 cos 3 x where x is a real number?
f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]
What is the derivative of x Times Square root of xx plus 1?
F(x)=x*Sqrt(x^2+1) let f(x)=x let g(x)=Sqrt(x^2+1) F'(x)=f'(x)*g(x)+f(x)*g'(x) f'(x)=1 Use chain rule: g'(x)=(x)*(x^2+1)^(-1/2) F'(x)=Sqrt(x^2+1)+(x^2)/Sqrt(x^2+1)
What is the first derivative of modulus function?
f(x)=|x| |x| = sqrt(x^2) f(x) = sqrt (x^2) f'(x)=1/2sqrt(x^2) d/dx(x^2) f'(x) = 2x /2sqrt(x^2) f'(x) = x/sqrt(x^2) f'(x)= x /|x| --------------------- Note: d/dx [sqrt(x^2] = d/dx [x^(1/2)] =(1/2)x^(-1/2)=1/2x^(1/2)=1/2sqrt(x)
