x2+7x-18 = (x+9)(x-2) when factored
The answer to this depends on what you mean by "x 7" If you mean: x2 -7x, then it can be factored out as x(x - 7) If you mean: x2 - x7, then you can factor it out as: x2(1 - x5) If you mean: x2 - x + 7, then it can not be factored If you mean: (x2 - x)7, then the inner term can be factored, giving you (x[x - 1])7 If you mean something else, then you will need to be more clear with your question.
It is (x+3)(x+4) when factored
x2-6x+8 = (x-2)(x-4) when factored
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
If you mean: x squared -7x +12 then it is (x-3)(x-4) when factored
x^2 +7x+12 = (x+3)(x+4) when factored
x2+7x-18 = (x+9)(x-2) when factored
It is (x-3)(x-4) when factored
x2-7x-18 = (x-9)(x+2) when factored
x2-7x+6 = (x-1)(x-6) when factored.
x2+7x-44 = (x-4)(x+11) when factored
x2-7x-44 = (x+4)(x-11) when factored
x2+7x+12
x2 + 7x - 56 cannot be factorised.
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
x^2 +7x+6 = (x+1)(x+6) when factored