sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
honestly, a reaaallly happy smile :) y=x^2 -has a turning point at (0,0) -the range is R+ or [0, infinity) -the domain is R or (-infinity, infinity)
The domain of y = x0.5 is [0,+Infinity]. There are no X and Y intercepts for this function.Not asked, but answered for completeness sake, the range is also [0,+Infinity]. That is why there are no intercepts.Taken one step further, if you include the domain [-Infinity,0) in your analysis, you must include the imaginary range (i0,iInfinity] in your result set.
The domain of a function pertains to all the x values The range of a function pertains to all the y values So domain and range do not get confused, this can be easily remembered by the order of the how the first letter of the word appears in the English alphabet. d, domain, goes before r, range x goes before y domain = x values range = y values ill try to add to the previous writer. previously, he wrote what the domain and range are for easier functions, but not how to determine them. more generally, what the domain is, is what you can put into a function, which in simpler cases, is jus x. to find what you can put in, it helps to find what you cant put in for x, meaning, where is the graph of the function discontinuous. for example, if we look at the function f(x)=1/(1-x) if we put 1 in for x, then the denominator goes to zero and the function is discontinuous at that x value, therefore 1 will not be included in the domain, but everything else will be included since there are no other disconinuities. the domain will end up looking like this- (-infinity,1), (1,infinity). now for the range, all you have to do is find what you can get out of the function from what you can put in, which can usually be done by putting the values you see for the domain in. putting negative infinity in for x in f(x)=1/(1-x) you get zero and putting one in you get infinty. putting it together you get (-infinity,0), (0,infinity) for your range. p.s. as i stated before, more generally, your domain is more so what you put into your function, so it is not always x, for example, in the case of a function of 2 variables such as f(x,y), what you can put in for both x and y will make up your domain, not just x, and y will most certainly not be your range, rather it will be the values of f(x,y).
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
The domain of the sine function is [-infinity, +infinity].The range is [-1, +1].The sine function is periodic. It repeats itself every 360 degrees or 2PI radians.
The domain of the sine function is all real numbers, or (-∞, ∞). Note the curly brackets around this interval, when a domain or range includes positive or negative infinity, it is never inclusive.
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
Sine does not converge but oscillates. As a result sine does not tend to a limit as its argument tends to infinity. So sine(infinity) is not defined.
Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.
(-infinity, infinity)
X = All Real Numbers or -infinity (is less than) x (is less than) infinity
anything can be put into it so... (-infinity,infinity)
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
The domain of a function is the set of values of the independent variable for which the function is valid. In practice, this is the allowable values of X or, in this case, theta. The sine and cosine functions have a domain of all numbers from negative infinity to positive infinity. The tangent function, however, is sine(theta) / cosine(theta). Cosine(theta) has value of zero at theta equal to pi / 2, 3pi/2, 5pi/2, ... in the positive direction, and -pi/2, -3pi/2, -5pi/2, ... As a result, tangent(theta) is undefined at these values, so the domain of tangent is all numbers from negative infinity to positive infinity except all numbers n pi/2 where n is odd.
Domain, in math terms, is the set of possible x values. This changes with your function. f(x)=x, for example, has a domain of negative infinity to infinity. However, f(x)=squareroot of x can only be positive, as otherwise it would go to imaginary numbers. Hence, its domain is 0 to inifinity.
x=y^2 may be written as y=+/-sqrt(x) The domain for sqrt(x) is [0, infinity). The range is also [0, infinity) However, y=+/-sqrt(x) is not a function, because one element in the domain has two values in the range set.