There are several ways and one of the ways is as follows:-
Let the coordinates be (x1, y1) and (x2, y2) for (-1, -6) and (-3, -5)
(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y--6)/(-5--6) = (x--1)/(-3--1)
(y+6)/(1) = (x+1)/(-2)
y+6 = -1/2x -1/2
y = -0.5x-6.5
The above equation can be written in the form of x+2y+13 = 0
Remember that a minus minus is equal to a plus so for instance -5--6 = 1
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
It works out as: y = 2x+1
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: 14y = -x-9.5 or x+14y+9.5 in its general form
The equation is y = 1/8x because there is no y intercept and by doing some homework you'll find it correct
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
Choose the equation of the line that contains the points (1, -1) and (2, -2).
-1
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
1
The equation for the given points is y = x+4 in slope intercept form
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
The straight line equation works out as: 3y = x
The straight line equation works out as: 3y = x
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
Points: (8, 2) and (0, 0) Slope: 1/4 or 0.25 Equation: y = 0.25x