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There are several ways and one of the ways is as follows:-
Let the coordinates be (x1, y1) and (x2, y2) for (-1, -6) and (-3, -5)
(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y--6)/(-5--6) = (x--1)/(-3--1)
(y+6)/(1) = (x+1)/(-2)
y+6 = -1/2x -1/2
y = -0.5x-6.5
The above equation can be written in the form of x+2y+13 = 0
Remember that a minus minus is equal to a plus so for instance -5--6 = 1
What else can I help you with?
What is an equation of the locus of points equidistant from the points 4 1 and 10 1?
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
Write the equation for a line that intersects points 1 3 and 2 5?
It works out as: y = 2x+1
How do you find the straight line equation passing through the points -7 -3 and -1 -4?
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25
What is the equation of the line passing through the points -2.5 -0.5 and 4.5 -1 on the coordinated grid?
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: 14y = -x-9.5 or x+14y+9.5 in its general form
What is the equation of the straight line that extends from the origin to the centre of the points 3 2 and 5 -1 on the Cartesian plane giving thorougher details of your work?
The equation is y = 1/8x because there is no y intercept and by doing some homework you'll find it correct
How can you find equation of the line passing thruogh two points?
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
What equation of the line that contains the point 1 -1 and 2 -2?
Choose the equation of the line that contains the points (1, -1) and (2, -2).
What points are on the line given by the equation y 2x - 3?
-1
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Which set of points are on the line y 8x - 8?
To find the set of points on the line described by the equation ( y = 8x - 8 ), you can substitute various values of ( x ) into the equation to find corresponding ( y ) values. For example, if ( x = 0 ), then ( y = -8 ), giving the point ( (0, -8) ). If ( x = 1 ), then ( y = 0 ), giving the point ( (1, 0) ). Thus, the points ( (0, -8) ) and ( (1, 0) ) are on the line.
Which is not an equation of the line that passes through the points 1 1 and 5 5?
The equation for the given points is y = x+4 in slope intercept form
What are the points that lie on the line 3x-y2?
1
What is the equation of the line passing through the points 2 2 and 3 1?
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
Find the equation of the line below.2-1?
To find the equation of a line, you typically need a point and a slope. If the line is represented in the form (y = mx + b), where (m) is the slope and (b) is the y-intercept, you can substitute the values accordingly. If you provide specific points or characteristics of the line, I can help you derive the exact equation. Please clarify the details related to "2-1."
What is an equation of the locus of points equidistant from the points 4 1 and 10 1?
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
What is the equation of the line containing the points (3 1) (9 3) (27 9)?
The straight line equation works out as: 3y = x
What is the equation of the line containing the points (3 1) (9 3) and (27 9)?
The straight line equation works out as: 3y = x
