To plot points remember the format (x,y).
The points you provided will not cross the x-axis because they have a zero for x.
(0,3) start from the middle(origin) and count three spaces up(counting by 1).Place a dot.
(0,11) start from the middle(origin) and count eleven spaces up(counting by 1).Place a dot.
Slope = 7--3 over 0-8 = -5/4
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
If you mean points of (1, -2) and (-9, 3) then it works out as about 11
Points: (0, 0) and (10, 30) Slope: 3
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
The easy way is to plot the x- and y-intercept points and draw the lines that passes through those two points. If y = 0, then we have 3x = -2and x = -2/3. So the x-intercept point is (-2/3, 0). If x = 0, then we have -y = -2and y = 2. So the y-intercept point is (0, 2). Plot the points and draw the line.
Slope of line through (3,5) and (0,11) = (change in y coordinate)/(change in x coordinate) = (5 - 11)/(3 - 0) = -6/3 = -2
you should've studied
Points: (3, 0) and (0, -9) Slope: 3 Equation: y = 3x-9
If the points are: (0, 3) and (8, -3) then the slope works out as -3/4
Solve for y.-x + 2y = 3 add x to both sides2y = x + 3 divide by to both sidesy = (1/2)x + 3/2 y-intercept is 3/2 or 1.5, so you have one point (0, 1.5)Set y = 0 to find the x-intercept.-x + 2(0) = 3-x = 3x = -1 so you have another point (-1, 0).Plot these points and draw a straight line that passes through them.Or, plot the point (0, 1.5) and you can find as many points as you want by using the slope, 1/2.
The distance between the points of (4, 3) and (0, 3) is 4 units
whose got the most assists The 11 point player has 4 and the other has 0.
Points: (3, -6) and (-3, 0) Slope: -1 Equation: y = -x-3
Points: (0, 0) and (2, 6) Slope: 3
you get 1 point for a draw. 0 points for a loss. and 3 points if you win.
The points of contact are the solutions to the simultaneous equations:3x - y = 5 → y = 3x - 52x² + y² = 129Substitute for y in (2) using (1) gives: 2x² + (3x - 5)² = 129→ 2x² + 9x² - 30x + 25 - 129 = 0→ 11x² - 30x - 104 = 0→ (11x - 52)(x + 2) = 0So11x - 52 = 0→ x = 52/11→ y = 3×52/11 - 5 = 101/11orx + 2 = 0→ x = -2→ y = 3×(-2) - 5 = -11→ the points of contact are (-2, -11) and (52/11, 101/11) ≈ (4.72, 9.18)