Any value less than or equal to 144 square units.
The rectangle could be
12 * 12 with area = 144
or 11 * 13 and area = 143
or 10 * 14 and area = 140
or 1 * 23 and area = 23
or 0.1 * 23.9 and area = 2.39
or 0.01 * 23.99 and area = 0.2399
etc
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The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
The perimeter of the rectangle is the sum of its 4 sides.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.