Let the shorter leg be x-5 and the other leg be x. Use Pythagoras' theorem: (x-5)2+x2 = 625 (x-5)(x-5)+x2 = 625 2x2-10x+25 = 625 2x2-10x+25-625 = 0 2x2-10x-600 = 0 Solving the above using the quadratic equation formula works out as: x = -15 or x = 20, so it must be the latter because dimensions can't be negative. Therefore:the shorter leg is 15 cm
A quadratic equation is an equation with the form: y=Ax2+Bx+C The most important point when graphing a parabola (the shape formed by a quadratic) is the vertex. The vertex is the maximum or minimum of the parabola. The x value of the vertex is equal to -B/(2A). Once you have the x value, just plug it back into the original equation to get the corresponding y value. The resulting ordered pair is the location of the vertex. A parabola will be concave up (pointed downward) if A is +. It will be concave down (pointed upward) if A is -. It is often helpful to find the zeroes of a function when graphing. This can be done by factoring or using the quadratic formula. For every n units away from the vertex on the x-axis, the corresponding y value goes up (or down) by n2*A. Parabolas are symetrical along the vertex, which means that if one point is n units from the vertex, the point -n units from the vertex has the same y value. As an example take the following quadratic: 2x2-8x+3 A=2, B=-8, and C=3 The x value of the vertex is -B/2A=-(-8)/(2*2)=2 By plugging 2 into the original equation we get that the vertex is at (2,-5) 3 units to the right (x=5) has a y value of -5+32*2=13. This means that 3 units to the left (x=-1) has the same y value (-1,13). If you need a clearer explanation, ask a math teacher.
The tangent equation that touches the circle 2x^2 +2y^2 -8x -5y -1 = 0 at the point of (1, -1) works out in its general form as: 4x +9y +5 = 0
You have two options. You can purchase 24" cross pieces for your grid, to turn the 2X4 sections into 2X2 sections, or you can purchase 2X4 tiles that look like 2X2 tiles. Ceilume's Stratford Style is a good example.
LET angle 1= 2xangle 2= x"find the value of x"angle1 + angle2 = 902x + x = 903x = 903X = 30"subtitute the X with the equation"angle1 = 2x2(30)60angle2 = 30
It is a quadratic equation that has 2 solutions
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
2x2 + 3x - 20 = (x + 4)(2x - 5).
Without an equality sign the given quadratic expression can't be classed as an equation but knowing how to use the quadratic equation formula would be helpful when given such problems.
-7 therefore the quadratic equation has no real roots
That's not an equation - it doesn't have an equal sign. Assuming you mean 2x2 - 3x - 90 = 0, you can find the solution, or usually the two solutions, of such equations with the quadratic formula. In this case, replace a = 2, b = -3, c = -90.
There are no solutions to this quadratic equation because the discriminant is less than zero.
A quadratic equation is an equation where the highest exponent on the variable is 2. For example, the equation, y=2x2+3x-2 is a quadratic equation. The equation y=2x is not quadratic because the highest exponent on x is 1. (If there is no exponent on an x, then the exponent is 1.) The equation, y=x3+3x2-2 is not quadratic because the highest exponent is three. On a graph, a quadratic equation looks like a U or and upside down U. Here are some more example of quadratic equations: y=x2 y=3x2+2x-3 y=x2+5
2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
Using the quadratic equation formula the solutions are:- x = -27.0382854 and x = 90.5382854
Using the quadratic equation formula: x = 1 or x = -10
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