3 because 5- 2 is 3.
Points: (2, 4) and (5, 0) Distance: 5
Points: (-5, -2) and (3, 13)Distance works out as 17 units
distance = sqrt( (xf-xi)2 + (yf-yi)2 ) = sqrt( ((-3) - (1))2 + ((5) - (-1))2 ) = sqrt(52)
If you mean points of: (2, 5) and (-4, 8) Distance is the square root of (2--4)^2+(5-8)^2 = 6.708 rounded
square root of (5-9)^2+(1+6)^2
(Distance)2 = (2 - 5)2 + (6 - 2)2
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
Points: (2, 4) and (5, 0) Distance: 5
-2 & 5
(2-5)2+(5-7)2 = 13 and the square root of this is the distance which is about 3.60555 to 5 decimal places
The distance between (10, 5) and (5, -2) is sqrt[(10 - 5)2 + (5 + 2)2] = sqrt(52 + 72) = sqrt(25 + 49) = sqrt(74) = 8.602 (to 3 dp)
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
the distance between two points is length
If you mean points of (5, 5) and (1, 5) then the distance is 4
7.6158 (rounded)
5
Distance = (9-5)2+(-6-1)2 = 65 and the square root of this is the distance between the points which is about 8.062257748