Points: (2, 4) and (5, 0) Distance: 5
Points: (-5, -2) and (3, 13)Distance works out as 17 units
distance = sqrt( (xf-xi)2 + (yf-yi)2 ) = sqrt( ((-3) - (1))2 + ((5) - (-1))2 ) = sqrt(52)
If you mean points of: (2, 5) and (-4, 8) Distance is the square root of (2--4)^2+(5-8)^2 = 6.708 rounded
square root of (5-9)^2+(1+6)^2
(Distance)2 = (2 - 5)2 + (6 - 2)2
Points: (2, 4) and (5, 0) Distance: 5
-2 & 5
(2-5)2+(5-7)2 = 13 and the square root of this is the distance which is about 3.60555 to 5 decimal places
The distance between (10, 5) and (5, -2) is sqrt[(10 - 5)2 + (5 + 2)2] = sqrt(52 + 72) = sqrt(25 + 49) = sqrt(74) = 8.602 (to 3 dp)
the distance between two points is length
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
If you mean points of (5, 5) and (1, 5) then the distance is 4
7.6158 (rounded)
5
Distance = (9-5)2+(-6-1)2 = 65 and the square root of this is the distance between the points which is about 8.062257748
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.