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To clarify, since you you couldn't put in symbols: Which group of points are all on the line y=-2x+1?
If we are graphing over the real numbers, then there are an infinite number of points: all the points on the line.
We can say this mathematically as: "The set of all points (x,y) for which y=-2x+1"
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Line BC has an equation of a line y 2x plus 3 and line EF has an equation of a line y negative one over 2x plus 4. These two equations represent (5 points)?
If you mean y = 2x+3 and y = -1/2x+4 then the two lines are perpendicular to each other meeting at right angles.
Write the equation for a line that intersects points 1 3 and 2 5?
It works out as: y = 2x+1
What is the slope intercept form of a line passing through points 4-2 and 6-3?
Points: (4, -2) and (6, -3) Slope: -1/2 Straight line equation: y = -1/2x There is no y intercept.
Which equation represents a line that is parallel to the line y equals 3-2x?
5
What is the perpendicular distance from the point 2 4 to the straight line y equals 2x plus 10?
It is 2√5 ≈ 4.47 units.To solve this:Find the equation of the line perpendicular to y = 2x + 10 that passes through the point (2, 4);Find the point where this line meets y = 2x + 10Find the distance from this point to (2, 4) using PythagorasThe slope of the perpendicular line (m') to a line with slope m is such that mm' = -1, ie m' = -1/mFor y = 2x + 10, the perpendicular line has slope -1/2, and so the line that passes through (2, 4) with this slope is given by:y - 4 = -½(x - 2)→ 2y - 8 = -x + 2→ 2y + x = 10To find where this meets the line y = 2x + 10, substitute for y in the equation of the perpendicular line and solve for x:y = 2x + 102y + x = 10→ 2(2x + 10) + x = 10→ 4x + 20 + x = 10→ 5x = -10→ x = -2Now use one of the equations to solve for y:y = 2x + 10→ y = 2(-2) + 10→ y = -4 + 10 = 6This the perpendicular line from (2, 4) meets the line y = 2x + 10 at the point (-2, 6)The distance between these two points is given by:distance = √((-2 - 2)² + (6 - 4)²) = √(16 + 4) = √20 = 2√5 ≈ 4.47 units
