Presumably because the lines are plotted on the Cartesian plane. So the line intersects the y-axis at the point (0, y).
The standart form of the equation of a line is y = ax + bx + c. If you replace x with 0, then y = c. Thus, the y-intercept point is (0, c).
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y - x = 0 which is the same as y = x + 0 which is of the form y = mx + c where m is the slope and c is the intercept. Hence for y = x + 0, the slope is 1 ans the intercept is 0. The equation represents a line making 45 degrees to the a-axis and it passes through the origin.
The function would be in the form of ax2+c. The axis of symmetry would be the y-axis, or x = 0, because b would be zero. Likewise, the y-intercept is not important, as any value of c will still yield a vertex at the y-intercept.
To find the y-intercept from a graph - look at where the graph of the line intersects the y-axis. The point at where the graph of the line crosses the y-axis will be the y-intercept with the coordinates of (0,y) The point at which the line cuts the y – axis is called as y – intercept.You can locate the point by seeing the graph.Note:If you are given a linear equation say ax + by + c = 0Now if we plug x = 0 in the given equation we will get the y – intercept.y = -c/bIf the given equation is of the form y = mx + bb is the y – intercept of the line. Source: www.icoachmath.com
The standard equation of a straight line in the slope-intercept form is y = mx + c where m is the slope and c is the y intercept.3x - 6y = 12 can be re-written as 6y = 3x - 12 or y = 1/2x - 2.-2 is therefore the y intercept (this is when x = 0)The x intercept (when y = 0) can be obtained from the equation y = 1/2x - 2 : 0 = 1/2x - 2 : 1/2x = 2 : x = 4.
slope intercept form is y=mx+b (m is slope, b is y intercept) slope = 4, y intercept = -2 y = 4x -2