0
It is still uncertain, from this writing whether 'x+3' is dividing just the '11X-19' aspect, or whether it is meant to be dividing all of the preceding. Normally, as it is written, it means the former:
(a) Multiplication, in this problem, is done first, following the BODMAS rule:
2X3=6; 11X2=22; and 11X-19=-209
So, the problem now reads:
6+22+-209/(x+3)
ANS = 28-209/(x+3)
(b) If we assume the intended meaning is to divide the whole lot by x+3, in which case the original question should finish by saying, "all divided by x plus 3", the problem is set out such:
[2X3+11X2+11X-19]/(x+3)
= [6+22-209]/(x+3)
=[28-209]/(x+3)
ANS = 181/(x+3)
Still curious? Ask our experts.
Chat with our AI personalities
Ross
Steve
MaxineAdd your answer:
Earn +20 pts
Is x-3 a factor of 2x3-11x2 plus 12x plus 9?
Yes. 2x3 - 11x2 + 12x + 9 = (x - 3)(2x2 - 5x - 3) = (x - 3)(2x2 - 6x + x - 3) = (x - 3)(2x + 1)(x - 3) = (2x + 1)(x - 3)2
How do you solve this 2x3 - 11x2 plus 24x - 18 diveded by 2x - 3?
The real equation got messed up when I posted it, the real equation is this: 2x^3 - 11x^2 + 24x - 18 divided by 2x - 3 ^ = to the 3rd and 2nd power.
X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
Factor 4x5 plus 6x3 plus 6x2 plus 9?
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
What is 7 plus 2x3?
13
