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I suspect the answer is yes, but it all depends on the exact form of the equation.
The key letter in finding the axis of symmetry for a quadratic function in the standard form (y = ax^2 + bx + c) is (b). The axis of symmetry can be calculated using the formula (x = -\frac{b}{2a}), where (a) is the coefficient of (x^2). This formula provides the x-coordinate of the vertex of the parabola, which is also the line of symmetry.
Axisymmetry is a form of symmetry around an axis - also known as rotational symmetry.
Functions with a highest exponent of 2 are known as quadratic functions. They are typically expressed in the standard form ( f(x) = ax^2 + bx + c ), where ( a ), ( b ), and ( c ) are constants, and ( a \neq 0 ). Quadratic functions produce parabolic graphs that can open upwards or downwards, depending on the sign of the coefficient ( a ). Common characteristics include a vertex, axis of symmetry, and potential real or complex roots.
The form is not specified in the question so it is hard to tell. But two parabolas with different vertices can certainly have the same axis of symmetry.
An equation for a sideways parabola can be expressed in the form ( y^2 = 4px ) for a parabola that opens to the right, or ( y^2 = -4px ) for one that opens to the left. Here, ( p ) represents the distance from the vertex to the focus. The vertex of the parabola is at the origin (0,0), and the axis of symmetry is horizontal. If the vertex is not at the origin, the equation can be adjusted to ( (y-k)^2 = 4p(x-h) ), where ((h, k)) is the vertex.
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
The key letter in finding the axis of symmetry for a quadratic function in the standard form (y = ax^2 + bx + c) is (b). The axis of symmetry can be calculated using the formula (x = -\frac{b}{2a}), where (a) is the coefficient of (x^2). This formula provides the x-coordinate of the vertex of the parabola, which is also the line of symmetry.
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
The function would be in the form of ax2+c. The axis of symmetry would be the y-axis, or x = 0, because b would be zero. Likewise, the y-intercept is not important, as any value of c will still yield a vertex at the y-intercept.
Axisymmetry is a form of symmetry around an axis - also known as rotational symmetry.
Functions with a highest exponent of 2 are known as quadratic functions. They are typically expressed in the standard form ( f(x) = ax^2 + bx + c ), where ( a ), ( b ), and ( c ) are constants, and ( a \neq 0 ). Quadratic functions produce parabolic graphs that can open upwards or downwards, depending on the sign of the coefficient ( a ). Common characteristics include a vertex, axis of symmetry, and potential real or complex roots.
The form is not specified in the question so it is hard to tell. But two parabolas with different vertices can certainly have the same axis of symmetry.
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
It is y = -b/(2a)
An equation for a sideways parabola can be expressed in the form ( y^2 = 4px ) for a parabola that opens to the right, or ( y^2 = -4px ) for one that opens to the left. Here, ( p ) represents the distance from the vertex to the focus. The vertex of the parabola is at the origin (0,0), and the axis of symmetry is horizontal. If the vertex is not at the origin, the equation can be adjusted to ( (y-k)^2 = 4p(x-h) ), where ((h, k)) is the vertex.
Lewis Carroll wrote these lines about a quadratic:Yet what are all such gaieties to meWhose thoughts are full of indices and surds?x*x + 7x + 53 = 11/3