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Can you write a poem based on the standard form the axis of symmetry and the vertex of a quadratic equation?
Wiki User
∙ 9y ago
Lewis Carroll wrote these lines about a quadratic:
Yet what are all such gaieties to me
Whose thoughts are full of indices and surds?
x*x + 7x + 53 = 11/3
Wiki User
∙ 9y ago
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What is the maximum or minimum of a quadratic equation called?
The vertex.
What is the equation of the axis of symmetry and the vertex of the graph gx-2x-12x 6?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
How do you find the x value of the vertex of a quadratic equation?
It depends on the level of your mathematical knowledge. One way is to differentiate the quadratic equation and find the value of x for which the derivative is 0. The advantage of this method is that it works for turning points of polynomials of all degrees. The disadvantage is that you need to know differentiation. For a quadratic, an alternative, and simpler way is to write the equation in the form: y = ax2 + bx + c Then the x value of the vertex is -b/2a
What is the definition of a Vertex form of a quadratic function?
it is a vertices's form of a function known as Quadratic
How do you do a parabola?
A parabola is a graph of a 2nd degree polynomial function. Two graph a parabola, you must factor the polynomial equation and solve for the roots and the vertex. If factoring doesn't work, use the quadratic equation.
Fill in the blank The of the vertex of a quadratic equation is determined by substituting the value of x from the axis of symmetry into the quadratic equation?
D
What different information do you get from vertex form and quadratic equation in standard form?
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
What is the equation for vertex form?
The vertex form for a quadratic equation is y=a(x-h)^2+k.
What is the maximum or minimum of a quadratic equation called?
The vertex.
Always use the vertex and at least points to graph each quadratic equation?
You should always use the vertex and at least two points to graph each quadratic equation. A good choice for two points are the intercepts of the quadratic equation.
What things are significant about the vertex of a quadratic function?
It is a turning point. It lies on the axis of symmetry.
How do you find the vertex from a quadratic equation in standard form?
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
What is the formula for quadratic equation in vertex form?
y=2(x-3)+1
What is the equation of the axis of symmetry and the vertex of the graph gx-2x-12x 6?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
How would you use intercepts to find the vertex in a quadratic equation with two x intercepts?
The vertex must be half way between the two x intercepts
Find the equation of the axis symmetry and the coordinates of the vertex of the graph of each function for y equals 2x plus 4?
I'm assuming that you meant y = 2(x^2) +4. If it were only y = 2x +4, then this would be a linear equation and not a parabola. Anyways, use the equation x = -b/2a to find the x-value of your vertex AND your axis of symmetry. (Given the standard equation y = a(x^2) + bx + c) So, x = -0/2(2) - x = 0 (Axis of Symmetry) Now plug 0 back into your equation to find your y-value of your vertex. y = 2(0^2)+4 y=0 + 4 y = 4 Therefore Vertex = (0,4)
What is the standard equation for vertex at origin opens down 1 and 76 units between the vertex and focus?
Since the vertex is at the origin and the parabola opens downward, the equation of the parabola is x2 = 4py, where p < 0, and the axis of symmetry is the y-axis. So the focus is at y-axis at (0, p) and the directrix equation is y = -p. Now, what do you mean with 1 and 76 units? 1.76 units? If the distance of the vertex and the focus is 1.76 units, then p = -1.76, thus 4p = -7.04, then the equation of the parabola is x2 = -7.04y.
