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Yes, that's what a geometric sequence is about.
The terms are: 4, 8 and 16
un = u0*rn for n = 1,2,3, ... where r is the constant multiple.
No. Although the ratios of the terms in the Fibonacci sequence do approach a constant, phi, in order for the Fibonacci sequence to be a geometric sequence the ratio of ALL of the terms has to be a constant, not just approaching one. A simple counterexample to show that this is not true is to notice that 1/1 is not equal to 2/1, nor is 3/2, 5/3, 8/5...
a, ar, ar^2 and ar^3 where a and r are constants.