It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
(x+2)(x+2) or (x+2)^2
(x + 2)(x + 1)
x^3 + x^2 + x = x(x^2 + x + 1)
2(x + 2)
2+2y+x+xy=(x+2)(y+1)
4(x + 2)(x + 2)
(x^2 + 9)(x^2 + 5)
(x + 2)(x^2+4)
x(x^2 + 2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
No