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In order to combine terms, the variable(s) must be the same and the exponent(s) must be the same on the variables. Since you have an x2 term, x term, xy term and y term, none of the terms can be combined. So, the answer is: x2 + 4x + xy + 4y. The only thing you could do in this problem is to factor out a 4 from the 4x & 4y so another way to write this is: x2 + xy + 4(x + y).
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If xy plus y equals z then x equals?
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
Factor 2x squared plus 2x plus xy plus y?
4
Factor X squared y plus axy plus abx plus a squared b?
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
Xy plus yx equals 545 what is the value of x and y?
xy and yx are identical so you have 2xy = 545 ie xy = 272.5. Possible answers 5 and 54.5, 10.9 and 25 etc
What is the value of the expression 4x-2y plus xy when x equals -1and y equals 5?
To find the value of the expression 4x - 2y + xy when x = -1 and y = 5, we first substitute the values of x and y into the expression. This gives us 4(-1) - 2(5) + (-1)(5). Simplifying this further, we get -4 - 10 - 5, which equals -19. Therefore, the value of the expression is -19 when x = -1 and y = 5.
Factor 2xy - 4x plus 8y - 16?
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
Factor xy plus 2x plus 4y plus 8?
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
What is xy minus 2x plus 4y minus 8?
(y-2) (x+4)
Factor 2xy plus 4x plus 8y plus 16?
2xy + 4x + 8y + 16 = 2[xy + 2x + 4y + 8] = 2[x(y + 2) + 4(y + 2)] = 2(y + 2)(x + 4)
Factor completely xy - 2x plus 4y -8?
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
Factor xy - 2x plus 4y - 8?
(x + 4)(y - 2)
Factor xy-2x plus 4y-8?
(x + 4)(y - 2)
How do you factor xy-2x plus 4y-8?
(x + 4)(y - 2)
How do you solve 4x-y2 and 3x y5?
4x-y2=2xy 2x ? y5 if its plus its 7 xy
Collect like terms 3xy plus xy-4x plus x?
-1
How do you factor yz plus xy plus 4x plus 4z?
y(z+x) + 4(x+z)
Factor 4x squared plus 4x plus 2xy plus 2y?
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
