Can you improve the question? It's hard to tell what you mean.
This does not factor over the field of rational numbers. If does factor over the reals. Use the quadratic formula to find the roots for the related quadratic equation: x2-11x-10 = 0 Cal them r1 and r2. The factors are (x - r1) and (x - r2.)
x2 - 11x + 24 = (x - 3)(x - 8)
This is the equation we want to factorize: x2 - 11x + 18 And there are two answers (the numbers are the same, but +/- signs are inverted): 1. (x - 2)(x - 9) = x2 - 9x - 2x -(-18) = x2 - 11x + 18 2. (-x + 2)(-x +9) = x2 -9x -2x + 18 = x2 - 11x + 18
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
21
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
X2 -11x +10=(x - 1 )(x - 10)
x2 -11x-12= (x-12)(x+1)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
I assume you mean...,X2 + 11X + 10(X + 1)(X + 10)==============factored
This does not factor over the field of rational numbers. If does factor over the reals. Use the quadratic formula to find the roots for the related quadratic equation: x2-11x-10 = 0 Cal them r1 and r2. The factors are (x - r1) and (x - r2.)
x(6x - 11)
Not possible to be specific since you have not provided the sign of the term in x, but there are two possible factorisations; (x + 3)(x + 8) = x2 + 11x + 24 and (x - 3)(x - 8) = x2 - 11x + 24