Multiply the factors together to get the function itself.
You'll need to use basic distributive properties to multiply factors:
a(b+c) = ab + ac
(a+b)(c+d) = ac+ad+bc+bd
As a simple example,
(1+2)(3+4) = 1*3 + 1*4 + 2*3 + 2*4 = 3*7 = 21
Now, apply this to your factors, which are often given in the form (x+c).
For instance, given the following two factors of the function f(x), find the function:
Factors: (x+2), (x+3), x
1.Define the function as a product of its factors
f(x) = x(x+2)(x+3)
2. multiply the two binomial factors
f(x) = x*(x*x + x*3 + 2*x + 2*3)
3. multiply the result by the remaining factor (x)
f(x) = x*x*x + x*x*3 + x*x*2 + x*2*3
4.simplify the result
f(x) = x3 + 5x2 + 6x
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Do mean find the polynomial given its roots ? If so the answer is (x -r1)(x-r2)...(x-rn) where r1,r2,.. rn is the given list roots.
graph apex xD
7421
If the cubic polynomial you are given does not have an obvious factorization, then you must use synthetic division. I'm sure wikipedia can tell you all about that.
Find values of the variable for which the value of the polynomial is zero.