Sin (theta) can most easily be found on a scientific calculator. You can also approximate it with Taylor's Series...
sin(x) = SummationN=0toInfinity (-1N / (2N + 1) !) (x(2N+1)))
sin(x) = x - x3/3! + x5/5! - x7/7! + ...
Using only the four terms above, you can approximate sin(x) within about 0.000003 in the interval x = [-1, +1].
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
Sin theta of 30 degrees is1/2
(/) = theta sin 2(/) = 2sin(/)cos(/)
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
It's 1/2 of sin(2 theta) .
The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))
2 sin (Θ) + 1 = 0sin (Θ) = -1/2Θ = 210°Θ = 330°
you have to do the arcsin which is sin-1 on your calculator. i have not met anyone in my life who can do sin or arcsin in their head. not even my college teachers. your theta is equal to 20degrees
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
(Sin theta + cos theta)^n= sin n theta + cos n theta
The identity for tan(theta) is sin(theta)/cos(theta).
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).