log(2) = X
can be expressed exponentially like this, because by the definition of logs( base 10) this is what this means.
10^X = 2
take natural log each side
ln(10^X) = ln(2)
you have right to place X in front of ln
X ln(10) = ln(2)
X = ln(2)/ln(10) ( not ln(2/10)!! )
X = 0.3010299957
check
10^0.3010299957
= 2
checks
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
Find 102a if log2=a and log3=b B has no purpose in this question If a=log2, then 102a =102(log2)
log2(31000) = 1000 log2(3)log2(3) = 1.585 (rounded)1000 log2(3) = log2(31000) = 1,584.96(rounded)
How do you solve 4y plus x equals 8
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
Find 102a if log2=a and log3=b B has no purpose in this question If a=log2, then 102a =102(log2)
if y = 2x then x = log2 y
log2(31000) = 1000 log2(3)log2(3) = 1.585 (rounded)1000 log2(3) = log2(31000) = 1,584.96(rounded)
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
If 2x = 22 Then x = Log2 22
How do you solve 4y plus x equals 8
log1 + log2 + log3 = log(1*2*3) = log6
log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.
log2(8) = 3 means (2)3 = 8
X +13 equals 22, X equals nine