y = x2 is not even a problem or a question. As it stands, it doesn't have
a solution, and it doesn't require any.
Your best approach is to go back and review the material that you have
learned in your algebra class, so that you improve your understanding
of the fundamental concepts. As you review the course, it would be most
helpful to you to work the exercises that offer practice at each step of the
way, such as those that are typically assigned as homework during the
normal presentation of the course.
x=18
(2x)ysquared
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144
x = +13x = - 13
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
x2 = 6482 = 64x = 8
x: x2 - 81 = 0
x=18
(2x)ysquared
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144
x = +13x = - 13
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
X2 = k Take square root each side. X = (+/-) sqrt(k) ============
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)