To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
To find the length of side ( AB ) in the right triangle ( ABC ), we can use the Pythagorean theorem, which states that ( AB^2 = AC^2 + BC^2 ). Given ( AC = 7 ) and ( BC = 8 ), we have: [ AB^2 = 7^2 + 8^2 = 49 + 64 = 113 ] Taking the square root, we get: [ AB = \sqrt{113} ] Thus, the length of ( AB ) in simplest radical form is ( \sqrt{113} ).
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
To construct segment EF with a length equal to the sum of segments AB (5) and CD (8), first draw segment AB measuring 5 units. Then, from one endpoint of segment AB, use a compass to measure out 8 units to create segment CD. Finally, connect the endpoint of segment CD to the endpoint of segment AB to form segment EF, which will measure 13 units in total.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
The length of time from 5:50 am to 2:00 pm is 8 hours 10 minutes. It is 10 minutes to 6:00 am, 6 hours to 12:00 pm, and another 2 hours to 2:00 pm. That totals to be 8 hours 10 minutes.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
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To construct segment EF with a length equal to the sum of segments AB (5) and CD (8), first draw segment AB measuring 5 units. Then, from one endpoint of segment AB, use a compass to measure out 8 units to create segment CD. Finally, connect the endpoint of segment CD to the endpoint of segment AB to form segment EF, which will measure 13 units in total.