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If a -1-3 and b 11-8 what is the length of AB?
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
Is A(-1-3) and B(11-8) what is the length of ab?
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
AC 8 cm and CB 6 cm what is the length of segment AB?
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
If you are given 2 segments segment AB which is equal to the length of 5 and segment CD which is equal to the length of 8 how would you use the congruent segments to construct segment EF which is equa?
To construct segment EF with a length equal to the sum of segments AB (5) and CD (8), first draw segment AB measuring 5 units. Then, from one endpoint of segment AB, use a compass to measure out 8 units to create segment CD. Finally, connect the endpoint of segment CD to the endpoint of segment AB to form segment EF, which will measure 13 units in total.
How to solve this 8.333333 equals ab b to power of negative 1 1.8 equals ab b to power of 2?
8 1/3 = ab^-1, 1.8 =ab^2
If a (0 0) and b (8 2) what is the length of ab?
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
If A is the point -2 -4 and B is -8 4 what is the length of AB?
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
If A (-2 -4) and B (-8 4) what is the length of line AB?
End points: (-2, -4) and (-8, 4) Length of line AB: 10
If A(-2-4) and B(-8-4) what is the length of AB?
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
If A is the point -2 -4 and B is the point -8 4 what is the length of AB?
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
If A (-2 -4) and B (-8 4) what is the length of Ab?
Using the distance formula the length of ab is 5 units
If a -1-3 and b 11-8 what is the length of AB?
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
Is A(-1-3) and B(11-8) what is the length of ab?
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
How many hours is it from 5 50 am - 2 pm?
The length of time from 5:50 am to 2:00 pm is 8 hours 10 minutes. It is 10 minutes to 6:00 am, 6 hours to 12:00 pm, and another 2 hours to 2:00 pm. That totals to be 8 hours 10 minutes.
AC 8 cm and CB 6 cm what is the length of segment AB?
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
If A (-1 -3) and B (11 -8) what is the length of ab?
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If you are given 2 segments segment AB which is equal to the length of 5 and segment CD which is equal to the length of 8 how would you use the congruent segments to construct segment EF which is equa?
To construct segment EF with a length equal to the sum of segments AB (5) and CD (8), first draw segment AB measuring 5 units. Then, from one endpoint of segment AB, use a compass to measure out 8 units to create segment CD. Finally, connect the endpoint of segment CD to the endpoint of segment AB to form segment EF, which will measure 13 units in total.
