To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
8 1/3 = ab^-1, 1.8 =ab^2
The time from 8:17 AM to 11:00 AM is 2 hours and 43 minutes. To calculate this, you can subtract 8:17 from 11:00, which gives you 2 hours until 10:17 AM, plus an additional 43 minutes to reach 11:00 AM.
From 7:00 AM to 3:00 PM is a total of 8 hours. You can calculate this by counting the hours from 7 to 3, which includes 8:00, 9:00, 10:00, 11:00, 12:00, 1:00, and 2:00, before reaching 3:00 PM.
835
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
The length of time from 5:50 am to 2:00 pm is 8 hours 10 minutes. It is 10 minutes to 6:00 am, 6 hours to 12:00 pm, and another 2 hours to 2:00 pm. That totals to be 8 hours 10 minutes.
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8
six and a quarter 8:00 to 12:00 = 4:00 12:00 to 2:15 = 2:15 4:00 + 2:15 = 6:15
six 14:00 - 08:00 = 06:00 8 to 12 = 4 12 to 2 = 2 4 + 2 = 6
We can't see the drawing, so we don't know how QX is related to AB. Maybethat's the whole problem. Perhaps you ought to look at the drawing.