To find the length of the line segment AB between the points A(0, 0) and B(8, 2), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the coordinates, we have ( d = \sqrt{(8 - 0)^2 + (2 - 0)^2} = \sqrt{64 + 4} = \sqrt{68} ). Therefore, the length of AB is ( \sqrt{68} ), which simplifies to ( 2\sqrt{17} ).
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
To find the length of side ( AB ) in the right triangle ( ABC ), we can use the Pythagorean theorem, which states that ( AB^2 = AC^2 + BC^2 ). Given ( AC = 7 ) and ( BC = 8 ), we have: [ AB^2 = 7^2 + 8^2 = 49 + 64 = 113 ] Taking the square root, we get: [ AB = \sqrt{113} ] Thus, the length of ( AB ) in simplest radical form is ( \sqrt{113} ).
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
To find the length of segment AB between points A(9, 18) and B(1, 12), you can use the distance formula: [ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting in the coordinates, we get: [ AB = \sqrt{(1 - 9)^2 + (12 - 18)^2} = \sqrt{(-8)^2 + (-6)^2} = \sqrt{64 + 36} = \sqrt{100} = 10. ] Thus, the length of AB is 10 units.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
To find the length of side ( AB ) in the right triangle ( ABC ), we can use the Pythagorean theorem, which states that ( AB^2 = AC^2 + BC^2 ). Given ( AC = 7 ) and ( BC = 8 ), we have: [ AB^2 = 7^2 + 8^2 = 49 + 64 = 113 ] Taking the square root, we get: [ AB = \sqrt{113} ] Thus, the length of ( AB ) in simplest radical form is ( \sqrt{113} ).
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
The length of time from 5:50 am to 2:00 pm is 8 hours 10 minutes. It is 10 minutes to 6:00 am, 6 hours to 12:00 pm, and another 2 hours to 2:00 pm. That totals to be 8 hours 10 minutes.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
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