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If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
Use Pythagoras' theorem to find the length of the 3rd side
5 [3-4-5 triangle]
1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
3 ft = 1 yd 34 ÷ 3 = 11 r 1 → 34 = 11×3 + 1 34 ft = (11×3 + 1) ft = 11 × 3 ft + 1 ft = 11 yd 1 ft
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
Using the distance formula the length of ab is 5 units
The length is 3*sqrt(5) = 6.7082, approx.
Using the distance formula the length of ab is 5 units
36/√3
1. ab x ac = ab+c Example: 2 x 22 = 21+2 = 23 2. ab ÷ ac = ab-c Examples: 35 ÷ 32 = 35-2 = 33 32 ÷ 35 = 32-5 = 3-3 3. a-b = 1/ab Example: 3-3 = 1/33
8 1/3 = ab^-1, 1.8 =ab^2
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
About 3% of the population is AB positive. 1% is AB negative.
If you mean points of (1, 1) and (3, -3) then the length works out as the square root of 20 which is about 4.472 rounded to 3 decimal places.
Use Pythagoras' theorem to find the length of the 3rd side