Length AB is 17 units
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
10 units
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
Length AB is 17 units
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
Using the distance formula the length of ab is 5 units
Using the distance formula the length of ab is 5 units
6.71
52.4 cm
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
h
End points: (-2, -4) and (-8, 4) Length of line AB: 10
LCM(a,b) = (ab)/(GCF(a,b)) 63 factors to [3 3 7] 15 factors to [3 5] common factors: [3] 63 * 15 / 3 = 315 ■