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If a rock on Earth is dropped in a vacuum and has an initial speed of 0 meters per second What is the rock's falling speed after 2 seconds?
Since there is no air, there is no air resistance so acceleration of free-fall is constant throughout the fall. Thus the first of the four equations of motion can be used.
v = u + at
where v = final velocity, u = initial velocity, a = constant acceleration, t = time of motion
v = 0 + (9.8 m/sec/sec)(2 sec) = 19.6 meters per second.
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Speed = (acceleration) x (time)
Acceleration of a dropped rock = gravity = 9.8 m/s2
Speed = (9.8) x (2) = 19.6 m/sec
What else can I help you with?
What is the height of a tower if a rock dropped from it hits the ground after falling for 2 seconds?
19.6 meters / 64.4 ft
A piece of metal has attained a velocity of 107.8 meters per second after falling for ten seconds what is its initial velocity?
the answer is 24-9 m/sec. yuor welcome
If a rock is dropped off a cliff with an initial speed of 0 meters per second what is the rocks speed after 5 seconds in meters per second if it encounters no air resistance?
If a rock is dropped from a cliff with an initial speed of 0 meters per second and encounters no air resistance, its speed after 5 seconds can be calculated using the formula for free fall: ( v = g \cdot t ), where ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 )) and ( t ) is the time in seconds. After 5 seconds, the speed of the rock would be ( v = 9.81 , \text{m/s}^2 \cdot 5 , \text{s} = 49.05 , \text{m/s} ). Thus, the rock's speed after 5 seconds would be approximately 49.05 meters per second.
A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?
176.4 meters
An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
What is the height of a tower if a rock dropped from it hits the ground after falling for 2 seconds?
19.6 meters / 64.4 ft
A piece of metal has attained a velocity of 107.8 meters per second after falling for ten seconds what is its initial velocity?
the answer is 24-9 m/sec. yuor welcome
What is the velocity of freely falling objects 5 seconds after being dropped?
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
Suppose an object in free fall is dropped from a building. Its starting velocity is 0 ms. What is the speed (in ms) of the object after falling 2 seconds Give your answer as a positive decimal.?
The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s.
If a rock is dropped off a cliff with an initial speed of 0 meters per second what is the rocks speed after 5 seconds in meters per second if it encounters no air resistance?
If a rock is dropped from a cliff with an initial speed of 0 meters per second and encounters no air resistance, its speed after 5 seconds can be calculated using the formula for free fall: ( v = g \cdot t ), where ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 )) and ( t ) is the time in seconds. After 5 seconds, the speed of the rock would be ( v = 9.81 , \text{m/s}^2 \cdot 5 , \text{s} = 49.05 , \text{m/s} ). Thus, the rock's speed after 5 seconds would be approximately 49.05 meters per second.
How long will it take an object dropped from a window to fall a distance of 78.4 meters?
4 Seconds
A 6.65 kg laundry bag is dropped from rest at an initial height of 3.20 m?
So? Whats the question? _______________________________ It doesn't matter what it is (well, if we ignore air resistance), in Earth's gravity the object will accelerate at 9.8 meters per second per second. Dropped from an altitude H, you can use the formula =(2/9.8*H)^0.5 to calculate the time it takes (in seconds) to the ground. In the absence of air resistance, it will take 0.808 seconds to fall. The speed of the falling object at any moment can be calculated as the time multiplied by 9.8 meters per second per second. In the absence of air resistance, the laundry bag will be falling at a speed of 7.9 meters per second when it hits.
When acceleration occurs?
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?
176.4 meters
What is the height of a ball dropped from 80 meters after 3 seconds?
The height of the ball after 3 seconds can be calculated using the formula for free fall: ( h = h_0 - \frac{1}{2} g t^2 ), where ( h_0 ) is the initial height (80 meters), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( t ) is the time in seconds. After 3 seconds, the height is ( h = 80 - \frac{1}{2} \times 9.81 \times (3^2) ), which simplifies to ( h = 80 - 44.145 ). Therefore, the height of the ball after 3 seconds is approximately 35.855 meters.
Ignoring the effects of air resistance what is the speed in of the object after falling 3 seconds?
Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
How far does something fall in 2.56 seconds?
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
