It is prime only for x = -4 and x = -7. For any other integer x, the value of this expression is not prime.
First of all, a Prime number is a number only divisible by two positive numbers: 1 and itself.
Factoring out the expression, we have:
x² + 11x + 30 = (x+5) (x+6)
So the result is divisible by at least two numbers, (x+5) and (x+6). The only cases where this lead to a prime number are the ones where one of the factors is 1 and the other isn't 0 (since 0 is not prime):
x = -4 => (-4 + 5) (-4 + 6) = 2
x = -7 => (-7 + 5) (-7 + 6) = (-2) (-1) = 2
If x must be a counting number, then there's no x for which the expression value is prime.
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is: x^2 +11x +24 = (x+8)(x+3) when factored
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
x^3 - 121x
X2 -11x +10=(x - 1 )(x - 10)
x^2 + 11x + 6 has no rational zeros.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is: x^2 +11x +24 = (x+8)(x+3) when factored
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
It cannot be factored because the discriminant is less than zero. Do you mean x2+11x-60 then if so it is (x-4)(x+15)