Without any equality signs the given expression can't be considered to be straight line equations.
Without a second independent equation, it's not a 'system' yet.
Thanks to the browser, it is not possible to tell what the inequalities are.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
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Without any equality signs the given expression can't be considered to be straight line equations.
y2x is an expression, which cannot be graphed because we don't know what it equals. y = 2x, y2 = x, and 2y (or y2) = x are all things that could actually be graphed.
Without a second independent equation, it's not a 'system' yet.
Thanks to the browser, it is not possible to tell what the inequalities are.
y2x - just double the coordinate of y to get x. xy12 - i have no idea
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
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2x + 2y = 14 eqn 12x - y = 5 eqn 2Solve for X and Y.Simplify eqn 2 to solve for y2x - y = 5subtract sx from both sides-y = 5 - 2xmultiple both sides by -1y = 2x - 5substitute 2x - 5 into eqn 1 for y2x + 2y = 142x + 2(2x -5) = 142x + 4x - 10 = 146x - 10 = 14add 10 to both sides6x = 24divide both sides by 10x= 4Substitute x = 4 into eqn 2y = 2(4) - 5y = 8 - 5y = 3X = 4 and y = 3
(4,1)
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2). Neither y2x nor x 2y5 is an equation.
It is an expression in two variables, x and y.