(x+2)=2x+20
x+2=2x+20
x-2x=20-2
-x=18
x=-18
proof
-18+2=2*-18+20
-16=-36+20
-16=-16
There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?
-10 and -11.
11
55 and 57
Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?
-10 and -11.
27, 29
11
5872345098234783904672083946728390752430689723409687298290843 theres your answer
55 and 57
Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3
They are (14, 15, 16).
Let x be one integerLet's say it is the bigger one.x-1 must be the other one since they are consecutive.x=2(x-1)+15x=2x+13-x=13x=-13 andx-1, the smaller one is -14Let's check.twice the smaller is -2815 more than -28 is -13 which is the bigger one.So the answer is -14 and -13
9 and 10 9 + 2(10) = 29
The sum of two consecutive integers can not be even unless both are even or both are odd.x+y=70y=4+2xx+(4+2x)=704+3x=703x=70-43x=66x=22y=70-22y=48The two numbers are 22 and 48. 22 is the smaller.