Let x be one integer
Let's say it is the bigger one.
x-1 must be the other one since they are consecutive.
x=2(x-1)+15
x=2x+13
-x=13
x=-13 and
x-1, the smaller one is -14
Let's check.
twice the smaller is -28
15 more than -28 is -13 which is the bigger one.
So the answer is -14 and -13
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
27, 29
5872345098234783904672083946728390752430689723409687298290843 theres your answer
They are (14, 15, 16).
The sum of two consecutive integers can not be even unless both are even or both are odd.x+y=70y=4+2xx+(4+2x)=704+3x=703x=70-43x=66x=22y=70-22y=48The two numbers are 22 and 48. 22 is the smaller.
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?
-10 and -11.
27, 29
11
(x+2)=2x+20 x+2=2x+20 x-2x=20-2 -x=18 x=-18 proof -18+2=2*-18+20 -16=-36+20 -16=-16
5872345098234783904672083946728390752430689723409687298290843 theres your answer
Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3
55 and 57
They are (14, 15, 16).
9 and 10 9 + 2(10) = 29
The sum of two consecutive integers can not be even unless both are even or both are odd.x+y=70y=4+2xx+(4+2x)=704+3x=703x=70-43x=66x=22y=70-22y=48The two numbers are 22 and 48. 22 is the smaller.