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There are 24C4 = 24*23*22*21/(4*3*2*1) = 10,626 of them, and I do not have the time to list them all.

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Q: What 4 number combinations are in the numbers 1-2-3-4-5-6-7-8-9-10-11-12-13-14-15-16-17-18-19-20-21-22-23-24?
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How many numbers can you make with 3 7 8 9?

14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.


What number combinations can be made with the numbers 1 2 3 4 5 6 7?

There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.


How many 4 number combinations are therefor 36 numbers?

There are: 36C4 = 58,905


How many 4-number combinations using numbers 0-9?

9000


How many combinations of 4 numbers can be made of 36 numbers if you can not repeat the numbers?

The number of combinations of 4 numbers that can be made from a set of 36 numbers without repeating any numbers is calculated using the combination formula. The formula for combinations is nCr = n! / r!(n-r)!, where n is the total number of options and r is the number of selections. In this case, n = 36 and r = 4. Therefore, the number of combinations is 36! / 4!(36-4)! = 36! / 4!32! = (36 x 35 x 34 x 33) / (4 x 3 x 2 x 1) = 58905 combinations.