There are 24C4 = 24*23*22*21/(4*3*2*1) = 10,626 of them, and I do not have the time to list them all.
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14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.There is 1 combinations with 7 numbers in them,7 combinations with 1 or 6 numbers in them,21 combinations with 2 or 5 numbers in them,35 combinations with 3 or 4 numbers in them.Notionally, there is also one combination with no numbers in it.In all then, there are 128 ( = 27) combinations.
There are: 36C4 = 58,905
9000
The number of combinations of 4 numbers that can be made from a set of 36 numbers without repeating any numbers is calculated using the combination formula. The formula for combinations is nCr = n! / r!(n-r)!, where n is the total number of options and r is the number of selections. In this case, n = 36 and r = 4. Therefore, the number of combinations is 36! / 4!(36-4)! = 36! / 4!32! = (36 x 35 x 34 x 33) / (4 x 3 x 2 x 1) = 58905 combinations.