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If x is the smallest, the other numbers are (x+1) and (x=+2).

2(x+1) + (x+2) = 5x - 14

2x + 2 + x + 2 = 5x -14

3x + 4 = 5x -14

4 = 5x - 3x - 14

4 + 14 = 5x - 3x

18 = 2x

9 = x

To verify...

(10 * 2) + 11 = 20 + 11 = 31

(5 * 9) - 14 = 45 - 14 = 31

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Q: What are 3 consecutive integers such that twice the middle integer plus the largest is 14 less than five times the smallest?
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