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7 - 6x- x2 = 0

so changing signs and reordering, x2 + 6x - 7 = 0

then x2 + 7x - x - 7 = 0

that is x(x + 7) - 1(x + 7) = 0

so that (x - 1)*(x + 7) = 0

which implies that x - 1 = 0 ie x = 1

or x + 7 = 0 ie x = -7

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Q: What are solutions to equation 7-6x-x2equals 0?
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