0
What else can I help you with?
How many solutions are there to the equation x3 - 7 0?
None because without an equality sign the given expression is not an equation and so therefore no solutions are possible.
How can you tell how many solutions a quadratic equation will have without solving it?
A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.
What determine how many solutions a quadratic equation will have and whether they are real or imaginary?
The quadratic equation is: Ax2+ Bx + C = 0-- The equation always has two solutions. They arex = 1/2A [ - B + sqrt(B2 - 4AC) ]x = 1/2A [ - B - sqrt(B2 - 4AC) ] .-- The solutions are real if ( B2 > or = 4AC ).-- The solutions are equal if ( B2 = 4AC ).-- The solutions are complex conjugates if ( B2 < 4AC ).-- The solutions are pure imaginary if ( B = 0 ) & (4AC>0 i.e. -4AC
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
What are the solutions to the equation 3(x-4)(x 5)0?
Without an equality sign the given expression can't be considered to be an equation and so therefore there are no solutions.
How many solutions does 0 equals 0 have?
0 = 0 is an identity and not an equation. Equations have solutions, identities do not.
If the discriminant of a quadratic equation is -4 how many solutions does the equation have?
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
What is the quadratic equation with solutions of 7i?
x2 + 49 = 0
How can you determine the number of solutions for an equation?
In general, you cannot: it all depends on the domain.x + 2 = 0 has no solutions is the set of positive integers but does have one if the domain is the integers.2x - 3 = 0 has no solutions if the domain is integers, but there is one solution if the domain is the rationals.x2 - 2 = 0 has no solutions if the domain is the rationals but there are two solutions if the domain is the reals.x2 + 2 = 0 has no solutions if the domain is the reals but there are two solutions if the domain is the complex numbers.Cos(x) = 1 has no solutions if the domain is (0, 360) but two solutions for the domain [0, 360].
What is the result if you add 0 on each side of an equation?
The solutions of the equation (if any) remain unchanged.
How many solutions are there to the equation x3 - 7 0?
None because without an equality sign the given expression is not an equation and so therefore no solutions are possible.
How can you tell how many solutions a quadratic equation will have without solving it?
A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.
What determine how many solutions a quadratic equation will have and whether they are real or imaginary?
The quadratic equation is: Ax2+ Bx + C = 0-- The equation always has two solutions. They arex = 1/2A [ - B + sqrt(B2 - 4AC) ]x = 1/2A [ - B - sqrt(B2 - 4AC) ] .-- The solutions are real if ( B2 > or = 4AC ).-- The solutions are equal if ( B2 = 4AC ).-- The solutions are complex conjugates if ( B2 < 4AC ).-- The solutions are pure imaginary if ( B = 0 ) & (4AC>0 i.e. -4AC
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Why quadratic equations have two solutions?
If the discriminant of b2-4ac of the quadratic equation is greater the 0 then it will have 2 solutions.
What does it mean if an equation equals 0 does it have one solution no solution or indefinitely many solutions?
It has infinitely many solutions.
What are the solutions to the equation 3(x-4)(x 5)0?
Without an equality sign the given expression can't be considered to be an equation and so therefore there are no solutions.
