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2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
work it out it's one more than the 8th and one less than the 10th * * * * * The above answer seems to make no sense here. It is not clear what you mean by a fraction sequence. It is not possible to go through the process for finding the nth term in an arithmetic, geometric or power sequence here. For school mathematics, sequences of fractions are, in fact composed of two simple sequences. One sequence defines the numerators and the other defines the denominators. In such cases, the nth term of the fraction sequence is the fraction given by the nth term of the numerator sequence divided by the nth term of the denominator sequence. For example: 1/1, 3/4, 5/9, 7/16, 9/25, ... The numerators are the odd number, with t(n) = 2n-1 The denominators are the squares of natural numbers with u(n) = n2 So, the nth term of the fraction sequence is (2n-1)/n2.
The sequence is too short to be certain but it could be tn = (n-1)2 + n2 = 2n2 -2n + 1
The rule that generates the sequence is Un = 9 + 2n (for n = 1, 2, ...
The nth term of the sequence is 2n + 1.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
The nth term of the sequence 2n + 1 is calculated by substituting n with the term number. So, the tenth term would be 2(10) + 1 = 20 + 1 = 21. Therefore, the tenth term of the sequence 2n + 1 is 21.
Oh, what a happy little question! To find the 10th term of the sequence 2n + 1, we simply substitute n with 10. So, 2(10) + 1 equals 21. That's the 10th term of this lovely sequence. Just remember, there are no mistakes in math, only happy little accidents.
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
2n(n+1)
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
2n-1 to the tenth term = 1
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.