If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
Yes and it works out that x = 3 and y = 4
(2,-2)
4x+3y=20 / 2x-3y=4 ..... In this case x=4 and y=4/3
4
If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
Yes and it works out that x = 3 and y = 4
(2,-2)
If you mean: 6x+6y = 36 and 2x-2y = 20 then its works out x = 8 and y = -2
4x+3y=20 / 2x-3y=4 ..... In this case x=4 and y=4/3
4
Usually elimination is used on two equations and is called linear combination. You could solve for "y." That is customary. 2x+3y=1 3y=-2y+1 y=(-2/3)x+1/3
2x(4+8) = 2x(4) and 2x(8)
Let's explain with an example: 2x - 7y = 11 5x + 7y = 3 To solve this system of equations by elimination we "add" the second equation to the first equation. So basically: 2x + 5x - 7y + 7y = 11 + 3 Which then symplifies to: 7x = 14 and x = 2 Then plug x = 2 into the original equation: 5(2) + 7y = 3 Which leads to: y = -1 So the solution is (2,-1).
Solving by the elimination method gives: x = 3 and y = 2
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
You are given: 2x + 5y = 3 -x + 3y = -7 Multiply the second equation by 2, so now your two equations look like this: 2x + 5y = 3 -2x + 6y = -14 Now add these two equations together and solve for your remaining variable: 11y = -11 y = -1 Finally, plug this value for y into either of the original equations and solve for x: 2x + 5y = 3 2x + (5)(-1) = 3 2x - 5 = 3 2x = 8 x = 4 So your final answer is x = 4 and y = -1.