Q: What is every term of a sequence is 1?

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every next term is 4 smaller than previous so 7th term = -23

If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.

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First 18 terms of the sequence are: 1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597, 2584. Every third term is 2,8,34,144,610,2584. These are all even so the largest number is likely 2.

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That's the famous Fibonacci sequence, where every term is the sum of the previous two.

The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.

every next term is 4 smaller than previous so 7th term = -23

If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.

The 19th term of the sequence is 16.

The nth term of the sequence is 2n + 1.

Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.

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The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.

The nth term of the sequence is 3n - 2.

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First 18 terms of the sequence are: 1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597, 2584. Every third term is 2,8,34,144,610,2584. These are all even so the largest number is likely 2.