If we look at the absolute value of the terms, we see that they follow the pattern that the nth term is 2n.
In order to account for the alternating signs, we are going to need to have the 2n multiplied by (-1)^(n-1), yielding 2n*(-1)^(n-1).
Check the first few terms,
2*1*(-1)^(1-1)=2
2*2*(-1)^(2-1)=-4
2*3*(-1)^(3-1)=6
Looks good.
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The Nth term in the series is [ 2N ] .
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
By "the nth term" of a sequence we mean an expression that will allow us to calculate the term that is in the nth position of the sequence. For example consider the sequence 2, 4, 6, 8, 10,... The pattern is easy to see. # The first term is two. # The second term is two times two. # The third term is two times three. # The fourth term is two times four. # The tenth term is two times ten. # the nineteenth term is two times nineteen. # The nth term is two times n. In this sequence the nth term is 2n.
multiplies by 2