No. Here is a proof by counterexample that it does not.Given ab + bc + ca = 3:Assume toward a contradiction that abc is a cube. Then a = b = c.Without loss of generality, let a = 2, b = 2, and c = 2.Then ab = 4, bc = 4, and ca = 4.ab + bc + ca = 4 + 4 + 4 = 12.Therefore, 12 = 3, which is false, and so the original statement is false.
a(3+b)+c(3+b) * * * * * This is easy to finish: . . . = (a + c)(3 + b).
Area = 0.5*AB*BC*sin(ABC) = 0.5*(2x+1)*(x+2)*0.5 = 3 So, (2x+1)*(x+2) = 12 2x2 + 5x + 2 = 12 2x2 + 5x - 10 = 0 x = 1.31 (to 3 sf)
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
That factors to (b + 3)(a + c)
No. Here is a proof by counterexample that it does not.Given ab + bc + ca = 3:Assume toward a contradiction that abc is a cube. Then a = b = c.Without loss of generality, let a = 2, b = 2, and c = 2.Then ab = 4, bc = 4, and ca = 4.ab + bc + ca = 4 + 4 + 4 = 12.Therefore, 12 = 3, which is false, and so the original statement is false.
0
a(3+b)+c(3+b) * * * * * This is easy to finish: . . . = (a + c)(3 + b).
I-90 East to US-95 North/BC-95 North to BC-3 East/AB-3 East to AB-22 North to AB-533 East to AB-2 North.
Area = 0.5*AB*BC*sin(ABC) = 0.5*(2x+1)*(x+2)*0.5 = 3 So, (2x+1)*(x+2) = 12 2x2 + 5x + 2 = 12 2x2 + 5x - 10 = 0 x = 1.31 (to 3 sf)
AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
a(b+3)+b(b+3)
(a + 3)( b + 2)
(Coefficient of friction of plane ab) + 2(Coefficient of friction of plane bc) = 1 Coefficient of friction of plane ab = Coefficient of friction of plane bc = 1/3 = 0.33333......