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Using Pythagoras' theorem it is 20 times the sq rt of 2

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Q: What is the diagonal measurement of a 20 x 20 square?
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What is the diagonal measurement a 20 x 20 square?

Using Pythagoras it is 20 times square root of 2


What is the diagonal of a 20ft x 20ft square?

Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.


12inch x 12 inch square what is the diagonal measurement?

A 12" x 12" square has a diagonal measurement of: 16.97 inches.


What is the diagonal measurement of a 12 x 16 rectangle?

The diagonal is 20.


What is the diagonal measurement of a 600 mm x 600 mm square paver?

The diagonal of the paver is about 848.53mm


How long is the diagonal of a 20 x 20 square?

Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 20 × √2 ≈ 28.3 units


What is diagonal measurement of a 6 ft x 6 ft square?

About 8.5 feet.


What would the diagonal measurement of a 12 foot x 12 foot square?

14 ft


What is the diagonal measurement of 36 foot by 36 foot square?

To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.


What is the diagonal measurement for a square 10' x 16'?

10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet


What is the diagonal length of a square 20feet x 20 feet?

About 28.28 feet.


What is the diagonal measurement of 40' x 60'?

To find the diagonal measurement of a rectangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 60' rectangle can be calculated as follows: Diagonal = √(40^2 + 60^2) = √(1600 + 3600) = √5200 ≈ 72.11 feet. Therefore, the diagonal measurement of a 40' x 60' rectangle is approximately 72.11 feet.