14 because
(7 square root of 2)squared then doubled is196
Square root of 196 is 14.
There is trigonometry that shortens this.
4
Perimeter of a figure is the sum of its side lengths. In a square, all four sides are the same length. So, the perimeter of a square whose side length is 8.5 is 4 x 8.5 = 34.
The area is 72 square units. Explanation: the diagonal,d, is the hypotenuse of a rt. triangle whose legs are both s, the side of the square, so d2= s2 + s2 = 2s2 Therefore , the area of the square , s2 = d2/2 = (12)2/ 2 = 144/2 = 72.
The length of the diagonal of any square whose sides are a whole number of units.
3.54Improved Answer:-Let a side of the square be x and use Pythagoras' theorem to find its length:-2x2 = 25x = sqrt of 12.5Area = sqrt 12.5*sqrt 12.5 = 12.5So the area of the square = 12.5 square units
The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
The square's diagonal is 11.314 cm
4
Using Pythagoras's theorem, you will find that the diagonal is sqrt(2) = 1.4142 cm (approx),
This is solved by pythagoras theorem: The longest length of a right angled triangle is equal to the square root of the sum of the other lengths squared. Therefore, 52 is 25, + 122 which is 144 = 169. The square root of 169 if i remember correctly is 13. So 13cm
Easiest thing to do here would be to draw a diagram and label the sides with their lengths and draw a line for the diagonal. You can see the diagonal forms part of a right-angled triangle, with its shorter lengths 35 cm and 12 cm. So using Pythagoras's Theorem, x2 = 352 + 122 = 1369 x = square root of 1369 = 37 cm.
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
Using Pythagoras, the length of the side can be calculated: Since it is a square, the two shorter lengths are the same, so: 2 x side2 = diagonal2 => side = sqrt(diagonal2 / 2) And once the side is known, the area can be calculated: area = side2 = diagonal2 / 2
The diagonal of a 46' x 46' square is 65.05 feet.
Perimeter of a figure is the sum of its side lengths. In a square, all four sides are the same length. So, the perimeter of a square whose side length is 8.5 is 4 x 8.5 = 34.