The sequence 13, 14, 15, 16, 17, 18, 19, 20 is an arithmetic progression where each term increases by 1. The nth term can be expressed by the formula ( a_n = 12 + n ), where ( n ) is the term number starting from 1. For example, for ( n = 1 ), ( a_1 = 12 + 1 = 13 ), and for ( n = 8 ), ( a_8 = 12 + 8 = 20 ).
To find the nth term formula for the sequence -4, -1, 4, 11, 20, 31, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11, which are increasing by 2. This indicates a quadratic relationship. The nth term formula can be derived as ( a_n = n^2 + n - 4 ).
The sequence 6, 13, 20, 27 increases by 7 each time. This indicates it is an arithmetic sequence with a common difference of 7. The nth term can be expressed as ( a_n = 6 + 7(n-1) ), which simplifies to ( a_n = 7n - 1 ). Thus, the nth term is ( 7n - 1 ).
Un = 29 - 9n
They are: nth term = 6n-4 and the 14th term is 80
The nth term of the sequence is expressed by the formula 8n - 4.
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
+9
Oh, dude, chill. The nth term for this sequence is -7n + 27. But like, who really needs to know that? Just enjoy the numbers, man.
Willies
The sequence 13, 14, 15, 16, 17, 18, 19, 20 is an arithmetic progression where each term increases by 1. The nth term can be expressed by the formula ( a_n = 12 + n ), where ( n ) is the term number starting from 1. For example, for ( n = 1 ), ( a_1 = 12 + 1 = 13 ), and for ( n = 8 ), ( a_8 = 12 + 8 = 20 ).
To find the nth term formula for the sequence -4, -1, 4, 11, 20, 31, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11, which are increasing by 2. This indicates a quadratic relationship. The nth term formula can be derived as ( a_n = n^2 + n - 4 ).
The sequence 6, 13, 20, 27 increases by 7 each time. This indicates it is an arithmetic sequence with a common difference of 7. The nth term can be expressed as ( a_n = 6 + 7(n-1) ), which simplifies to ( a_n = 7n - 1 ). Thus, the nth term is ( 7n - 1 ).
Un = 29 - 9n
To find the nth term in this sequence, we first need to determine the pattern. The differences between consecutive terms are 5, 7, 9, and 11 respectively. These differences are increasing by 2 each time. This indicates that the sequence is following a quadratic pattern. The nth term for this sequence can be found using the formula for the nth term of a quadratic sequence, which is Tn = an^2 + bn + c.
This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.=================================The 'N'th term is: [ 23 - 3N ].
The sequence 5, 10, 20, 40, 80 can be identified as a geometric progression where each term is multiplied by 2. The nth term can be expressed as ( a_n = 5 \times 2^{(n-1)} ), where ( a_n ) is the nth term. Thus, for any integer ( n ), you can find the term by substituting ( n ) into this formula. For example, the 1st term is 5, the 2nd term is 10, and so on.