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10 coins are tossed once .The probalilty of getting exactly eight heads is?
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
What is the probability of getting a factor of 10?
1 out of 2
What is the probality of not getting 1 out of 2 dice?
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
What is the probability of rolling a 4 on a 10-sided dice?
If there is a different number on each face of the die and no numbers a repeated it is a 1 in 10 chance.
What are the chances of for the probability 2 to 5?
The chances of picking a number between 2 to 5 is 4/10 if the numbers to be picked from are 1-10. However, if the numbers to be picked from are 1-100, then the probability drops to 4/100.
What is the probability of getting two prime numbers 1-10?
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
10 coins are tossed once .The probalilty of getting exactly eight heads is?
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
What is the probability of getting a factor of 10?
1 out of 2
Theoretical probability of rolling a factor of 10 on a number cube?
The factors of 10 are the numbers that divide 10 evenly: 1, 2, 5 and 10. To answer your question, you have to figure out what the probability of rolling one of these numbers is on a number cube.
What is the probability of choosing a divisor of 48 numbers 1-50?
The probability is 10/50 = 1/5.
What the probability of getting not a yellow sweet if there 3 yellow sweets and 10 blue sweets?
Probability of getting not a yellow sweet if there 3 yellow sweets and 10 blue sweets is 10/13.
What is the probality of not getting 1 out of 2 dice?
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
What is the probability of getting less than 10 when you roll a dice?
A die normally has six sides with the numbers 1 to 6 on them, so any roll will be less than 10 and thus the probability of getting less than 10 with a die is 1. With two normal dice, the sum of the digits on the dice added together ranges from 2 to 12 and the probability of getting less than 10 is the same as 1 minus the probability of getting 10 or more. There are 36 ways the two dice can fall and 10 can be achieved in 3 ways (4&6, 5&5, 6&4), 11 can be achieved in 2 ways (5&6, 6&5) and 12 in 1 way (6&6). Thus the probability of getting 10 or more with 2 dice is (3+2+1)/36 = 6/36 = 1/6 So the probability of getting less than 10 is 1-1/6 = 5/6
A number is chosen at random from the first 10 whole number What is the probability that it is not exactly divisible by 3?
the first 10 whole numbers are numbers 1 to 10 and in those numbers only 3 numbers are divisible by 3 in which 3, 6 and 9 therefore the probability of from those figures that the numbers won't be divisible by 3 is 7/10 or 70%.
What is the probability of rolling a 4 on a 10-sided dice?
If there is a different number on each face of the die and no numbers a repeated it is a 1 in 10 chance.
What is the probability of 1 to 10 to get a number greater then 3?
There are 10 numbers {1, 2, ..., 10} The solution set contains {4, 5, ...,10} - 7 numbers in total → probability = number of successful tries/total number of tries = 7/10 = 0.7
What is the probability of selecting a prime number from the numbers one through 10?
It is 0.4
